| HOLOTA, Petr | |
APRIORI ESTIMATES OF THE DISTURBING POTENTIAL IN THE SOLUTION OF THE GEODETIC BOUNDARY VALUE PROBLEM |
Proceedings of Research Works 1998. - Roè.44. - Zdiby : VÚGTK, 1998. - S.45-53. - ISBN 80-85881-10-1 |
Abstract. The purpose of this paper is to discuss apriori
estimates (bounds) for the disturbing potential and its part
representing higher degree harmonic components. An estimate was
also obtained for a horizontal component of the gradient of the
disturbing potential. The disturbing potential was
treated as a solution of the geodetic boundary value problem and
the estimates are considered in terms of the norm assigned to
Lebesgue's space of square integrable functions on the boundary of
the solution domain.
Abstrakt. Èlánek pojednává o apriorních odhadech (mezích) pro
poruchovœ potenciál a jeho çást representující vyšší harmonické
komponenty. Odhad byl získán i pro horizontální komponentu
gradientu poruchového potenciálu. Poruchovœ potenciál je chápán
jako øešení geodetického okrajového problému a odhady jsou
uvaÅovány ve smyslu normy v Lebesgueov³ prostoru funkcí
integrovatelnœch s druhou mocninou na hranici oblasti øešení.
Introduction
Geodetic computations mostly have a quantitative character and a
numerical realization of various quantities or functions represents
a target to be achieved. Nevertheless any computation and also the
computation of the (quasi-)geoid has also its functional-analytic
aspect bearing a qualitative nature.
For illustration recall Stokes' problem in the
exterior SR of a sphere of radius R, i.e. in
SR º {x Î R3; |x| > R}.
Here |x| = (åi = 13xi2)1/2 and xi, i = 1,2,3, are rectangular
Cartesian coordinates in Euclidean three-dimensional space R3.
The solution of the problem is sought as a function
T which is harmonic in SR and such that
|
R |
¶T
¶|x|
|
(x) + 2 T(x) = áx,grad T(x)ñ+ 2 T(x) = - R Dg(x) for |x| = R , |
| (1) |
where á ,ñ means the scalar product. If we expand
T and Dg in spherical harmonics, i.e.,
|
T(x) = |
¥ å
n = 0
|
|
æ ç
è
|
|
R
|x|
|
|
ö ÷
ø
|
n+1
|
Tn |
æ ç
è
|
|
x
|x|
|
|
ö ÷
ø
|
and Dg = |
¥ å
n = 0
|
Dgn, |
| (2) |
where Tn and Dgn are Laplace's surface harmonics
of degree n, it follows then that for |x| = R we have
|
T(x) = T1 |
æ ç
è
|
|
x
|x|
|
|
ö ÷
ø
|
+ |
¥ å
n = 0,n 1
|
|
R
n-1
|
Dgn |
æ ç
è
|
|
x
|x|
|
|
ö ÷
ø
|
, |
| (3) |
provided that Dg1 = 0. Thus T is
determined apart from the first degree harmonic component T1.
Note, however, that for the well known (physical) reasons
associated with the position of center of the coordinate system we
usually put T1 = 0.
Let now ¶SR be the boundary of SR. Under the above
notation we easily deduce that
|
|
ó õ
|
¶SR
|
T2 dS £ R2 |
¥ å
n = 0,n 1
|
|
ó õ
|
¶SR
|
(Dgn)2 dS = R2 |
ó õ
|
¶SR
|
(Dg)2 dS |
| (4) |
which implies
|
||T||L2(¶SR) £ R||Dg||L2(¶SR) , |
| (5) |
where ||.||L2(¶SR) means the norm of a function from
L2(¶SR), i.e. from the space of square integrable
functions on ¶SR .
(In the title we
have taken the liberty of replacing the latin a priori with the
single apriori for estimates of this kind.)
In case that a part of the solution represented by low degree
harmonics is known (e.g. from global geopotential models), we can
split T as T = T¢+ T¢¢, where
|
T¢(x) = |
N å
n = 0
|
|
æ ç
è
|
|
R
|x|
|
|
ö ÷
ø
|
n+1
|
Tn |
æ ç
è
|
|
x
|x|
|
|
ö ÷
ø
|
, T¢¢(x) = |
¥ å
n = N+1
|
|
æ ç
è
|
|
R
|x|
|
|
ö ÷
ø
|
n+1
|
|
R
n-1
|
Dgn |
æ ç
è
|
|
x
|x|
|
|
ö ÷
ø
|
|
| (6) |
and N > 1. Hence
|
|
ó õ
|
¶SR
|
(T¢¢)2 dS £ |
æ ç
è
|
|
R
N
|
|
ö ÷
ø
|
2
|
|
¥ å
n = N+1
|
|
ó õ
|
¶SR
|
(Dgn)2 dS £ |
æ ç
è
|
|
R
N
|
|
ö ÷
ø
|
2
|
|
ó õ
|
¶
SR
|
(Dg)2 dS |
| (7) |
and it is obvious that
|
||T¢¢||L2(¶SR) £ |
R
N
|
||Dg||L2(¶SR) |
| (8) |
which in contrast to (4) is a more favourable estimate. It
gives also a possibility to estimate how T¢¢ may
change in dependence on an incremental change of Dg.
Indeed, due to the linearity of Stokes' problem we have
||dT¢¢||L2(¶SR) £ (R/N)||d(Dg)||L2(¶SR),
where dT¢¢ and d(Dg) are the incremental changes of
T¢¢ and Dg, respectively. Recall, however, that similarly as above we
have to suppose that d(Dg1) = 0.
Finally, putting
[ . ] = w-1/2|| . ||L2(¶SR), where
w = 4pR2 means the area of the sphere ¶SR, we
also have
[ dT¢¢ ] £ (R/N)
[ d(Dg) ] .
Example 1. The preceeding inequality contains some parameters.
Numerically, taking e.g.
[ d(Dg) ] = 10-5 ms-2 (i.e. 1 mgal), R = 6378 km and
N = 100, we obtain that
[ dT¢¢ ] £ 0.64 m2s-2.
Moreover, dividing this inequality by g = 9.8 ms-2, we arrive at
[ dT¢¢ ]/g £ 0.06 m, which enables us to interpret our
apriori estimate of
[ dT¢¢ ] in a more telling way, i.e. in
terms of geoid undulations.
In reality (Molodensky's problem) the solution domain does not
coincide with the exterior of the sphere and in the boundary
condition the direction of the derivative is not perpendicular to
the boundary. In consequence the orthogonal decomposition of T
(i.e., T = T¢+ T¢¢) and of the right hand side Dg as
used in (6) does not hold anymore. A more general approach is
needed.
Let U stand for the potential of the normal gravity
of the Earth and DW and Dg be the
potential and the (vectorial) gravity anomaly, respectively. These
anomalies are related to U and to an adopted model
of the Earth surface. We will denote the exterior of this model by
W and recall that for the boundary ¶W of W we
usually use the term ``telluroid''. Moreover, we will assume
that W¢ = R3 - [`
(W)] (where
[`(W)] means the closure of W) is a starshaped
domain at the origin with the Lipschitz boundary such that
áx,nñ >
0 for almost all x Î
¶W
and n denoting the outer unit normal of ¶W,
see (Holota, 1996; 1997a,b).
Now we are ready to write that in general the problem is to find
T which is harmonic in W and such that
|
áh,grad Tñ+ T = f on ¶W , |
| (9) |
where f = DW + áh,Dgñ.
The vector
h = - [Mij]-1grad U,
provided that for
[Mij] = [¶2U/¶xi¶xj] and x Î ¶W
the Hessian: det [Mij(x)]
0 . Note that for the
standard choice of U the vector h is close to x/2.
As is well-known for an arbitrary constant vector c the
function u = ác,grad Uñ is harmonic in W and
represents a non-trivial solution
of (9) in case of f = 0. Recall, however, that this
solution is ruled out by the following asymptotic condition
|
T(x) = c/|x| + O(|x|-3) for x® ¥ . |
| (10) |
It completes the formulation of the problem. Here c is a
constant and O means the usual Landau symbol.
For reasons associated with our direct approach, we still put
s = háh,nñ-1 , c = áh,nñ-1 , g = - fáh,nñ-1 ,
provided that áh,nñ-1
0 on ¶W,
cf. (Holota, 1996, 1997a). Under this notation (9) turns into
|
ás,grad Tñ+ cT = - g on ¶W . (9)¢ |
|
Finally, note that this paper is an extended version of (Holota, 1997c).
Horizontal Component of the Gradient
In geodesy and in a number of related areas (e.g. in inertial
navigation) we frequently need also information concerning the
regularity of T along the boundary of SR. In other words we
need an estimate of
|
( Tt )2 = |
1
R2
|
|
æ ç
è
|
|
¶T
¶f
|
|
ö ÷
ø
|
2
|
+ |
1
R2cos2f
|
|
æ ç
è
|
|
¶T
¶l
|
|
ö ÷
ø
|
2
|
|
| (11) |
which on ¶SR is the squared magnitude of the total horizontal
component of the gradient of T. We try to get it in terms of the space
L2(¶SR). This has an important interpretation since with a high
accuracy we can put
|
|
ó õ
|
¶SR
|
( Tt )2 dS = g2 |
ó õ
|
¶SR
|
( x2 + h2 ) dS , |
| (12) |
where
x, h are the components of the deflection of the vertical in the
meridian and in the prime vertical.
As a starting point we use the following identity
|
0 = |
ó õ
|
SR
|
2|x| |
¶u
¶|x|
|
Du dx = |
ó õ
|
SR
|
|grad u|2 dx+ R |
ó õ
|
¶SR
|
|
é ê
ë
|
ut2 - |
æ ç
è
|
|
¶u
¶|x|
|
|
ö ÷
ø
|
2
|
|
ù ú
û
|
dS |
| (13) |
valid for any harmonic function u in SR which is continuous
together with its derivatives up to the boundary ¶SR,
see (Hörmander, 1975) or (Moritz, 1977). Thus it holds also
for the solution of Stokes' problem. When in addition Stokes's
boundary condition is used, it follows that
|
|
ó õ
|
¶SR
|
Tt2 dS = |
ó õ
|
¶SR
|
|
æ ç
è
|
Dg + |
2
R
|
T |
ö ÷
ø
|
2
|
dS- |
1
R
|
|
ó õ
|
SR
|
| grad T |2 dx |
| (14) |
and subsequently
|
|
ó õ
|
¶SR
|
Tt2 dS = |
2
R2
|
|
ó õ
|
¶SR
|
T2 dS+ |
3
R
|
|
ó õ
|
¶SR
|
T Dg dS+ |
ó õ
|
¶SR
|
(Dg)2 dS |
| (15) |
since
|
|
ó õ
|
SR
|
| grad T |2 dx- |
2
R
|
|
ó õ
|
¶SR
|
T2 dS = - |
ó õ
|
¶SR
|
|
æ ç
è
|
|
¶T
¶|x|
|
+ |
2
R
|
T |
ö ÷
ø
|
T dS = |
ó õ
|
¶SR
|
T Dg dS |
| (16) |
for T being the solution of Stokes' problem.
Using now inequality (4) from the introduction, we arrive
at
|
|
ó õ
|
¶SR
|
Tt2 dS £ 6 |
ó õ
|
¶SR
|
(Dg)2 dS . |
| (17) |
Similarly, in the case of the residual disturbing potential T¢¢, using
inequality (7), we easily deduce that
|
|
ó õ
|
¶SR
|
(T¢¢t)2 dS £ c |
ó õ
|
¶SR
|
(Dg)2 dS , |
| (18) |
where for N ® ¥
monotonously from above. This, however, does not represent such a
strong improvement as in the case of T and T¢¢, cf. inequality
(7). The obvious interpretation is that the use of high degree
geopotential models does not diminish the local variability
of T¢¢ (i.e. derivatives of T¢¢) in such a measure like in the
case of the value of the residual disturbing potential T¢¢.
A Non-Spherical Case
Let T be a harmonic function in W such that it satisfies the
boundary condition (9)¢. Suppose that
SR º {x Î R3; |x| > R} is contained in W. Now in analogy to the
spherical case, we split T into two parts: T¢,
represented by a finite sum of low degree harmonics and T¢¢ which
is harmonic in W and such that asymptotically
|
T¢¢(x) = O(|x|-N-2) for x® ¥ . |
| (20) |
Thus T = T¢+ T¢¢. Assuming now that T¢ is known, we try to
estimate T¢¢ in terms of the norm || . ||L2(¶W)
of the space L2(¶W), i.e., our aim is to find
an upper bound for
|
||T¢¢||L2(¶W) = |
é ë
|
|
ó õ
|
¶W
|
(T¢¢)2 dS |
ù û
|
1/2
|
. |
| (21) |
For this purpose we multiply equation (9)¢ by T¢¢ and
integrate it over ¶W. We obtain
|
((T¢¢,T¢¢)) = |
ó õ
|
¶W
|
|
_ g
|
T¢¢ dS , |
| (22) |
where
|
((T¢¢,T¢¢)) = - |
ó õ
|
¶W
|
T¢¢ás,grad T¢¢ñ dS - |
ó õ
|
¶W
|
c·(T¢¢)2 dS |
| (23) |
and
[`g] = g +ás,grad T¢ñ+ cT¢, which in terms of (9)¢ represents
a reduced right hand side. Moreover, following (Holota, 1996,1997b), we can
write for the first integral on the right hand side of (23) that
|
- |
ó õ
|
¶W
|
T¢¢ás,grad T¢¢ñ dS = |
ó õ
|
W
|
|grad T¢¢|2 dx- |
1
2
|
|
ó õ
|
¶W
|
L·(T¢¢)2 dS , |
| (24) |
where L = ácurl(n×s),nñ .
Remark 1. For the harmonic T¢¢ (24) represents a
generalized version of Green's identity. Indeed, for
s = n we have L = 0 and in this case (24) is a
consequence of the usual Green's identity. In (Holota, 1996, 1997b)
we can also find a geometrical interpretation of L.
For ((T¢¢,T¢¢)) we now have
|
((T¢¢,T¢¢)) = |
ó õ
|
W
|
|grad T¢¢|2 dx+ |
ó õ
|
¶W
|
K·(T¢¢)2 dS , |
| (25) |
where
K = - c- L/2 .
In the sequel we will need a lower estimate of ((T¢¢,T¢¢)) and an
upper estimate for the right hand side in (22).
A Lower Estimate
Putting D = W- [`(S)]R, we can write
|
((T¢¢,T¢¢)) ³ |
ó õ
|
SR
|
|grad T¢¢|2 dx+ |
ó õ
|
D
|
|grad T¢¢|2 dx-k |
ó õ
|
¶W
|
áx,nñ·(T¢¢)2 dS , |
| (26) |
where
|
k = supess[ áx,nxñ-1|K(x)| ] . |
| (27) |
x Î ¶W
Here we suppose that in computing the
essential supreme value we deal with a Lebesgue measurable function
defined and bounded almost everywhere on ¶W. (Loosely
speaking, we can say that k does not reflect extremes achieved on
sets of a zero Lebesgue measure.) In addition from Green's
identity, we deduce that
|
|
ó õ
|
¶W
|
áx,nñ·(T¢¢)2 dS = R |
ó õ
|
¶SR
|
(T¢¢)2 dS - 3 |
ó õ
|
D
|
(T¢¢)2 dx- |
ó õ
|
D
|
áx,grad (T¢¢)2ñ dx , |
| (28) |
where the third integral on the right hand side can be estimated by
means of the inequality |ab| £ ea2/2 + b2/2e
with an arbitrary e > 0. Hence, using still
grad (T¢¢)2 = 2T¢¢grad T¢¢ and recalling that |x| £ R on D, we have
|
|
ó õ
|
¶W
|
áx,nñ·(T¢¢)2 dS £ R |
ó õ
|
¶SR
|
(T¢¢)2 dS + (e- 3) |
ó õ
|
D
|
(T¢¢)2 dx+ |
R2
e
|
|
ó õ
|
D
|
|grad T¢¢|2 dx |
| (29) |
and is clear that for e = 3 eq. (29) results in
|
|
ó õ
|
¶W
|
áx,nñ·(T¢¢)2 dS £ R |
ó õ
|
¶SR
|
(T¢¢)2 dS + |
R2
3
|
|
ó õ
|
D
|
|grad T¢¢|2 dx . |
| (30) |
This immediately yields
|
((T¢¢,T¢¢)) ³ (((T¢¢,T¢¢))) + |
æ ç
è
|
1 - |
kR2
3
|
|
ö ÷
ø
|
|
ó õ
|
D
|
|grad T¢¢|2 dx |
| (31) |
with
|
(((T¢¢,T¢¢))) = |
ó õ
|
SR
|
|grad T¢¢|2 dx- kR |
ó õ
|
¶SR
|
(T¢¢)2 dS . |
| (32) |
Our problem now is to examine (((T¢¢,T¢¢))). In SR we expand
T¢¢ in spherical harmonics, i.e.,
T¢¢(x) = ån = N+1¥(R/|x|)n+1T¢¢n(x/|x|),
where the summation starts with n = N + 1 in view of (20). We
know that
|
|
ó õ
|
¶SR
|
(T¢¢)2 dS = |
¥ å
n = N+1
|
|
ó õ
|
¶SR
|
(T¢¢n)2 dS . |
| (33) |
Simultaneously, using Green's identity, we easily deduce
|
(((T¢¢,T¢¢))) = |
1
R
|
|
¥ å
N+1
|
(n + 1 - kR2) |
ó õ
|
¶SR
|
(T¢¢n)2 dS . |
| (34) |
Hence, assuming that
N + 2 - kR2 > 0
and putting C(N) = (N + 2 - kR2)/R, we arrive at
|
(((T¢¢,T¢¢))) ³ C(N) |
ó õ
|
¶SR
|
(T¢¢)2 dS . |
| (35) |
Remark 2. In (Holota, 1996) the existence, uniqueness and
stability of the solution of our oblique derivative boundary value
problem have been proved for 3 - kR2 > 0.
Thus N + 2 - kR2 > 0 for N > 1
is even a less restrictive assumption.
The last inequality together with (31) now yields
|
((T¢¢,T¢¢)) ³ C(N) |
ó õ
|
¶SR
|
(T¢¢)2 dS + |
æ ç
è
|
1 - |
kR2
3
|
|
ö ÷
ø
|
|
ó õ
|
D
|
|grad T¢¢|2 dx ³ |
|
|
³ |
3 - kR2
3R
|
|
é ë
|
(N + 2) |
ó õ
|
¶SR
|
(T¢¢)2 dS +R |
ó õ
|
D
|
|grad T¢¢|2 dx |
ù û
|
. |
| (36) |
and it is obvious that
|
((T¢¢,T¢¢)) ³ |
3 - kR2
R2
|
|
ó õ
|
¶W
|
áx,nñ·(T¢¢)2 dS |
| (37) |
in view of (30).
Finally, recalling that áx,nxñ is positive for almost all
x Î ¶W (according to the assumption made in the introduction),
we can conclude that
|
((T¢¢,T¢¢)) ³ c ||T¢¢||L2(¶W)2 with c = |
3 - kR2
R2
|
|
inf
x Î ¶W
|
[ áx,nxñ ] . |
| (38) |
An Estimate of the Solution
As already mentioned we need an upper estimate of the right hand
side of (22). It follows immediately from Hölder's inequality.
Indeed,
|
|
ó õ
|
¶W
|
|
_ g
|
T¢¢ dS £ || |
_ g
|
||L2(¶W)||T¢¢||L2(¶W) . |
| (39) |
Now combining (22), (38) and (39), we obtain
|
c ||T¢¢||L2(¶W)2 £ ((T¢¢,T¢¢)) = |
ó õ
|
¶W
|
|
_ g
|
T¢¢ dS £ || |
_ g
|
||L2(¶W)||T¢¢||L2(¶W) . |
| (40) |
In consequence
|
||T¢¢||L2(¶W) £ c-1 || |
_ g
|
||L2(¶W) |
| (41) |
and evidently also
||dT¢¢||L2(¶W) £ c-1 ||d[`g]||L2(¶W). Note that for ¶W of
mild slopes and curvatures and for a standard choice of the normal potential the
coefficient k is close to 2/R2 and áx,nxñ does not
differ from R strongly. Thus with some approximation c-1 is close to R.
This, however, yields an estimate on the level of efficiency as in (5).
Naturally, recalling (8), we expected more, i.e. a smaller factor in front of
the norm on the right hand side. We attempt to approach this problem in the next
section.
An Improved Estimate of an Approximate Solution in a Finite
Dimensional Space
Inspecting our computations, we can see that in (37) we have
not made full use of the favourable value of the factor
C(N). Indeed, the coefficients in (30) are not well balanced with
C(N) and (1 - kR2)/3 in (36). Therefore, our aim is to
modify (30).
In (29) we first try to estimate òD(T¢¢)2 dx by means of
ò¶SR(T¢¢)2 dS. This, however, is
associated with the non-stability of the downward continuation
problem. The estimate maybe obtained,
but for T¢¢ smoothed up to a certain degree only. In order to
smooth T¢¢ we will confine ourselves to a finite range of its
spherical harmonic components, i.e., in D we will approximate
T¢¢ by means of
|
T*(x) = |
nmax å
n = N+1
|
|
æ ç
è
|
|
R
|x|
|
|
ö ÷
ø
|
n+1
|
T¢¢n |
æ ç
è
|
|
x
|x|
|
|
ö ÷
ø
|
|
| (42) |
and will assume that nmax can be sufficiently high. Moreover, to
improve conditions for the computation of the desired estimate, we put
Tn* = (R/R0)n+1T¢¢n ,
where R0 is a greatest radius such that D is contained in
SR0 º {x Î R3; |x| > R0}. Thus,
|
T*(x) = |
nmax å
n = N+1
|
|
æ ç
è
|
|
R0
|x|
|
|
ö ÷
ø
|
n+1
|
Tn* |
æ ç
è
|
|
x
|x|
|
|
ö ÷
ø
|
. |
| (43) |
We evidently have
|
|
ó õ
|
¶SR
|
(T*)2 dS = R2 |
nmax å
n = N+1
|
qn+1 |
ó õ
|
¶S1
|
(Tn*)2 dS , |
| (44) |
where q = R0/R and by direct computation we obtain
|
|
ó õ
|
D
|
(T*)2 dx £ |
ó õ
|
R £ |x| £ R0
|
(T*)2 dx = R03 |
nmax å
n = N+1
|
|
1 - q2n-1
2n - 1
|
|
ó õ
|
¶S1
|
(Tn*)2 dS . |
| (45) |
Comparing now (44) and (45), we see clearly that we cannot deduce
the desired estimate for a full spectrum of harmonics since
qn+1 ® 0 for n ® ¥. Therefore, we will rather look
for a smallest positive constant c*, such that
|
R03 |
1 - q2n-1
2n - 1
|
£ c*R2qn+1 for n = N + 1, N + 2, ... , nmax . |
| (46) |
In other words, putting (after some arrangement)
|
f(q,n) = |
1 - q2n-1
(2n - 1)qn-2
|
, |
| (47) |
we are looking for the smallest c*, such that
|
Rf(q,n) £ c* for n = N + 1, N + 2, ... , nmax . |
| (48) |
Note that f(1,n) = 0 for all n. Thus for q = 1 we can put c* = 0.
In order to make the situation more transparent we give below
several values of f(q,n) for R = 6378 km and R0 = 6356 km, i.e.
for q = 0.9965506 :
| f(q,0) = 0.0034 | f(q,1000) = 0.0157 | f(q,2000) = 0.2490 |
| f(q,500) = 0.0054 | f(q,1500) = 0.0590 | f(q,2500) = 1.1213 |
Inspecting the table of f(q,n) quickly and taking e.g.
nmax = 1000, we can put c* = 0.016 R. Hence for the
mentioned parameters
|
|
ó õ
|
D
|
(T*)2 dx £ 0.016 R |
ó õ
|
¶SR
|
(T*)2 dS |
| (49) |
which enables to modify (29) as follows:
|
|
ó õ
|
¶W
|
áx,nñ·(T*)2 dS £ R[ 1 + 0.016(e- 3) ] |
ó õ
|
¶SR
|
(T*)2 dS + |
R2
e
|
|
ó õ
|
D
|
|grad T*|2 dx . |
| (50) |
Moreover, putting e.g. e = 22, we obtain
|
|
ó õ
|
¶W
|
áx,nñ·(T*)2 dS £ 1.30R |
ó õ
|
¶SR
|
(T*)2 dS + |
R2
22
|
|
ó õ
|
D
|
|grad T*|2 dx . |
| (51) |
Going now back to (36) and interpreting it for T* and N = 20,
we obtain
|
((T*,T*)) ³ |
22 (3 - kR2)
3R
|
|
é ê
ë
|
|
ó õ
|
¶SR
|
(T*)2 dS + |
R
22
|
|
ó õ
|
D
|
|grad T*|2 dx |
ù ú
û
|
, |
| (52) |
which in combination with (51) yields
|
((T*,T*)) ³ |
22 (3 - kR2)
3·1.30 R2
|
|
inf
x Î ¶W
|
[ áx,nxñ ] ||T*||L2(¶W)2 . |
| (53) |
Finally, recalling (39) which holds for T* as well, we can conclude that
|
||T*||L2(¶W) £ 0.17 c-1|| |
_ g
|
||L2(¶W) , |
| (54) |
provided that N = 20, nmax = 1000,
R = 6378 km and R0 = 6356 km. This estimate is somewhat weaker than that
resulting from (8) for the same parameters in the spherical case, but it shows
again the desired effect associated with the use of geopotential models.
Acknowledgements. The work on this paper has been supported by
the Grant Agency of the Czech Republic through Grant No. 205/96/0956.
This support is gratefully acknowledged.
References
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Naposledy aktualizováno: 21.8.1998
Dotazy a pøipomínky k této WWW stránce na Milan Talich, Alexandr Drbal.